Lambda type. More...

#include <sigc++/adaptors/lambda/base.h>

Inheritance diagram for sigc::lambda< T_type >:

Public Types
typedef lambda< T_type >	self

Public Member Functions
	lambda ()
	lambda (typename type_trait< T_type >::take v)
template<class T_arg >
lambda< lambda_operator<other < assign >, self, typename unwrap_lambda_type< T_arg > ::type > >	operator= (const T_arg& a) const
template<class T_arg >
lambda< lambda_operator<other < subscript >, self, typename unwrap_lambda_type< T_arg > ::type > >	operator[] (const T_arg& a) const

Detailed Description

template<class T_type>

struct sigc::lambda< T_type >

Lambda type.

Objects of this type store a value that may be of type lambda itself. In this case, operator()() executes the lambda (a lambda is always a functor at the same time). Otherwise, operator()() simply returns the stored value. The assign and subscript operators are defined to return a lambda operator.

Deprecated:

Use C++11 lambda expressions instead.

Member Typedef Documentation

template <class T_type>

typedef lambda<T_type> sigc::lambda< T_type >::self

Constructor & Destructor Documentation

template <class T_type>

sigc::lambda< T_type >::lambda ( )

inline

template <class T_type>

sigc::lambda< T_type >::lambda ( typename type_trait< T_type >::take  v )

inline

Member Function Documentation

template <class T_type>

template <class T_arg >

lambda<lambda_operator<other<assign>, self, typename unwrap_lambda_type<T_arg>::type> > sigc::lambda< T_type >::operator= ( const T_arg &  a ) const

inline

template <class T_type>

template <class T_arg >

lambda<lambda_operator<other<subscript>, self, typename unwrap_lambda_type<T_arg>::type> > sigc::lambda< T_type >::operator[] ( const T_arg &  a ) const

inline